Grade 3 Subtraction: Borrowing Across Zeros

Handle borrowing when there are zeros

What You'll Learn

  • Borrow when tens digit is 0
  • Chain borrowing across zeros
  • Apply careful checking

πŸ“–Zeros Are Tricky

When you need to borrow but the next digit is 0, you must borrow from the digit after that. 500 - 137: Borrow from hundreds, making it 4 hundreds and 10 tens. Then borrow from tens to ones.

πŸ’‘

When borrowing across a zero, the zero becomes 9 (because you borrowed 1 from it too)!

Worked examples

Real problems from the practice worksheets, solved one step at a time.

  1. Example 1

    300 βˆ’ 49 = ?

    1. Line up the numbers by place value and subtract each column from right to left.
    2. Ones: 0 is less than 9, so borrow 1 from the tens: 10 βˆ’ 9 = 1.
    3. Tens: 0 has nothing to lend, so it borrows 1 from the hundreds and becomes 10, then lends 1 to the ones, leaving 9. 9 βˆ’ 4 = 5.
    4. Hundreds: 3 lent 1, so it is now 2. 2 βˆ’ 0 = 2.
    5. 300 βˆ’ 49 = 251

    Answer: 251

  2. Example 2

    900 βˆ’ 431 = ?

    1. Line up the numbers by place value and subtract each column from right to left.
    2. Ones: 0 is less than 1, so borrow 1 from the tens: 10 βˆ’ 1 = 9.
    3. Tens: 0 has nothing to lend, so it borrows 1 from the hundreds and becomes 10, then lends 1 to the ones, leaving 9. 9 βˆ’ 3 = 6.
    4. Hundreds: 9 lent 1, so it is now 8. 8 βˆ’ 4 = 4.
    5. 900 βˆ’ 431 = 469

    Answer: 469

  3. Example 3

    302 βˆ’ 13 = ?

    1. Line up the numbers by place value and subtract each column from right to left.
    2. Ones: 2 is less than 3, so borrow 1 from the tens: 12 βˆ’ 3 = 9.
    3. Tens: 0 has nothing to lend, so it borrows 1 from the hundreds and becomes 10, then lends 1 to the ones, leaving 9. 9 βˆ’ 1 = 8.
    4. Hundreds: 3 lent 1, so it is now 2. 2 βˆ’ 0 = 2.
    5. 302 βˆ’ 13 = 289

    Answer: 289