Grade 6 Geometry: Area of Quadrilaterals

Parallelograms and trapezoids

What You'll Learn

  • Use area formulas
  • Apply to different shapes

📖Quadrilaterals

Different formulas for different shapes!

Worked examples

Real problems from the practice worksheets, solved one step at a time.

  1. Example 1

    A trapezoid has parallel bases of 9 ft and 17 ft and a height of 11 ft. What is its area in square feet?

    1. Area of a trapezoid = ½ × (base 1 + base 2) × height.
    2. Add the parallel bases: 9 + 17 = 26.
    3. Multiply by the height: 26 × 11 = 286.
    4. Take half: 286 ÷ 2 = 143. The area is 143 square feet.

    Answer: 143

  2. Example 2

    A parallelogram has a base of 6.5 m, a slanted side of 11 m, and a height of 7 m. What is its area in square meters?

    1. Area of a parallelogram = base × height. Use the straight-up height (7 meters), not the slanted side (11 meters).
    2. 6.5 × 7 = 45.5.
    3. The area is 45.5 square meters.

    Answer: 45.5

  3. Example 3

    A parallelogram has an area of 42 square meters and a base of 7 m. What is its height in meters?

    1. Area = base × height, so height = area ÷ base.
    2. 42 ÷ 7 = 6.
    3. Check: 7 × 6 = 42. The height is 6 meters.

    Answer: 6